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Contests/Gnit Sunday Open 002 (GSO002)/Problem 20 Optical Tweezer Manipulation of a Polar Nanoparticle: Interaction with Mirror Dipole of Grounded Conducting Sphere
Problem 20

Optical Tweezer Manipulation of a Polar Nanoparticle: Interaction with Mirror Dipole of Grounded Conducting Sphere

Finished
500 ptsLv.10 AdvancedElectromagnetism
2026/03/22 19:30〜2026/03/22 21:00
Author: admin

Problem Statement

In vacuum, a perfectly grounded conducting sphere of radius aaa is placed with its center at the origin O(0,0,0)O(0,0,0)O(0,0,0).

At a point A(0,0,r0)A(0,0,r_0)A(0,0,r0​) on the zzz-axis at distance r0r_0r0​ (r0>ar_0 > ar0​>a) from the sphere, a polar nanoparticle of negligible size is fixed. This particle possesses a permanent electric dipole moment of magnitude ppp (referred to simply as the "dipole").

Initially, the dipole direction points toward the origin OOO (i.e., in the −z-z−z direction).

While the particle's center of mass position is kept at point AAA, an external manipulation (such as an optical tweezer) quasi-statically rotates the dipole until it is finally parallel to the positive xxx-axis direction.

Find the work WWW done by the external force on the particle during this rotation.

The spatial extent of the dipole itself is sufficiently small compared to r0−ar_0 - ar0​−a, so it can be treated as an ideal point dipole. Let the proportionality constant in Coulomb's law be kkk. Gravity and all other interactions are neglected.

Constraints

  • Coulomb's law constant: k=9.0×109 N⋅m2/C2k = 9.0\times10^9 \text{ N}\cdot\text{m}^2/\text{C}^2k=9.0×109 N⋅m2/C2
  • Radius of conducting sphere: a=1.0×10−8 ma = 1.0\times10^{-8} \text{ m}a=1.0×10−8 m
  • Position of particle: r0=2.0×10−8 mr_0 = 2.0\times10^{-8} \text{ m}r0​=2.0×10−8 m
  • Magnitude of dipole moment: p=3.0×10−25 C⋅mp = 3.0\times10^{-25} \text{ C}\cdot\text{m}p=3.0×10−25 C⋅m

Input Format

The work W [J]W \text{ [J]}W [J] is expressed as W=X×10−18W = X\times10^{-18}W=X×10−18. Give the value of positive integer XXX.

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