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Contests/Gnit Weekly Challenge Beginner 004 (GWCB004)/Problem 1 Basics of Heat and Temperature Changes
Problem 1

Basics of Heat and Temperature Changes

Finished
100 ptsLv.2 BeginnerThermodynamics
2026/07/15 21:00〜2026/07/15 21:30
Author: admin02

Problem Statement

Consider the relationship between heat and temperature change when water in a cup is heated or cooled. Answer the following questions.

(1) A cup with a heat capacity of C0C_0C0​ contains water. How much heat, in J\mathrm{J}J, is required to raise the temperature of the entire cup by ΔT0\Delta T_0ΔT0​?

(2) The temperature of a mass m1m_1m1​ of water was raised from TaT_aTa​ to TbT_bTb​. What is the amount of heat, in J\mathrm{J}J, that the water absorbed? Let the specific heat capacity of water be cwc_wcw​.

(3) A constant amount of heat Q2Q_2Q2​ was applied to a mass m2m_2m2​ of water in a container using an electric heater, causing the temperature of the water to rise from TcT_cTc​ to TdT_dTd​. What is the specific heat of this water in J/(kg⋅K)\mathrm{J/(kg\cdot K)}J/(kg⋅K)? Assume that the heat capacity of the container and heat transfer to the outside can be neglected.

Constraints

・C0=80 J/KC_0 = 80 \text{ J/K}C0​=80 J/K ・ΔT0=15 K\Delta T_0 = 15 \text{ K}ΔT0​=15 K ・m1=0.20 kgm_1 = 0.20 \text{ kg}m1​=0.20 kg ・Ta=280 KT_a = 280 \text{ K}Ta​=280 K ・Tb=295 KT_b = 295 \text{ K}Tb​=295 K ・cw=4200 J/(kg\cdotK)c_w = 4200 \text{ J/(kg\cdot K)}cw​=4200 J/(kg\cdotK) ・m2=0.50 kgm_2 = 0.50 \text{ kg}m2​=0.50 kg ・Q2=31500 JQ_2 = 31500 \text{ J}Q2​=31500 J ・Tc=285 KT_c = 285 \text{ K}Tc​=285 K ・Td=300 KT_d = 300 \text{ K}Td​=300 K

Input Format

Let the answer to Part (1) be A1 JA_1\ \mathrm{J}A1​ J, the answer to Part (2) be A2 JA_2\ \mathrm{J}A2​ J, and the answer to Part (3) be A3 J/(kg⋅K)A_3\ \mathrm{J/(kg\cdot K)}A3​ J/(kg⋅K). As your final answer, calculate the value A1+A2−A3A_1 + A_2 - A_3A1​+A2​−A3​ and enter the resulting natural number as is.

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