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Contests/Gnit Sunday Open 003 (GSO003)/Problem 5 Deep-Sea Exploration: Absolute Refractive Index and Dispersion Sensor for an Unknown Liquid
Problem 5

Deep-Sea Exploration: Absolute Refractive Index and Dispersion Sensor for an Unknown Liquid

Finished
300 ptsLv.5 ElementaryWaves
2026/04/05 19:30〜2026/04/05 21:00
Author: admin

Problem Statement

To investigate the optical properties of a special liquid (liquid F) filling the deep ocean of an unknown ocean planet, a sensor made of a special optical crystal was lowered into the ocean.

The key element of the sensor is a prism with an equilateral triangular cross section PQR\text{PQR}PQR (apex angle ∠P=60∘\angle\text{P} = 60^\circ∠P=60∘). The prism is fully submerged in liquid F.

A laser beam is fired from the exploration vessel into liquid F and incident on face PQ\text{PQ}PQ (face 1). The light refracts and travels inside the prism, then reaches face PR\text{PR}PR (face 2).

The absolute refractive index of this crystal varies with the wavelength of the incident light (dispersion), but the absolute refractive index nfn_fnf​ of liquid F is assumed to be constant across the visible wavelength range.

Two experiments were performed:

[Experiment 1: Blue Light] For blue light, the crystal's absolute refractive index is ncBn_{cB}ncB​. As the angle of incidence θ0\theta_0θ0​ on face PQ\text{PQ}PQ was gradually increased from 0∘0^\circ0∘, the angle of incidence on face PR\text{PR}PR decreased (due to geometry). When θ0\theta_0θ0​ reached θ0B\theta_{0B}θ0B​, the angle of incidence on face PR\text{PR}PR decreased to the critical angle for total internal reflection, and transmitted light just began to emerge from face PR\text{PR}PR into liquid F.

[Experiment 2: Red Light] For red light, the crystal's absolute refractive index is ncRn_{cR}ncR​. Similarly increasing θ0\theta_0θ0​ from 0∘0^\circ0∘, the angle of incidence on face PQ\text{PQ}PQ at the moment transmitted light just begins to emerge from face PR\text{PR}PR (critical condition) is θ0R\theta_{0R}θ0R​.

All light propagation occurs in the plane containing triangle PQR\text{PQR}PQR. The absolute refractive index nfn_fnf​ of liquid F is greater than 111 but smaller than both ncBn_{cB}ncB​ and ncRn_{cR}ncR​.

Find sin⁡θ0R\sin\theta_{0R}sinθ0R​, the sine of the critical angle of incidence on face PQ\text{PQ}PQ for red light.

Constraints

  • Prism apex angle: ∠P=60∘\angle\text{P} = 60^\circ∠P=60∘
  • Crystal refractive index for blue light: ncB=2.8n_{cB} = 2.8ncB​=2.8
  • Crystal refractive index for red light: ncR=2.5n_{cR} = 2.5ncR​=2.5
  • Critical condition for blue light: sin⁡θ0B=0.6\sin\theta_{0B} = 0.6sinθ0B​=0.6
  • Angle of incidence θ0\theta_0θ0​ is measured from the normal (0∘≤θ0<90∘0^\circ \le \theta_0 < 90^\circ0∘≤θ0​<90∘)
  • nfn_fnf​ is constant (wavelength-independent)

Input Format

The value of sin⁡θ0R\sin\theta_{0R}sinθ0R​ is expressed in the rationalized form:

sin⁡θ0R=A−BC\sin\theta_{0R} = \frac{\sqrt{A} - B}{C}sinθ0R​=CA​−B​

where A,B,CA, B, CA,B,C are positive integers with gcd⁡(A,B,C)=1\gcd(A, B, C) = 1gcd(A,B,C)=1, and AAA has no perfect-square factor greater than 111.

Give the value of A×B×CA \times B \times CA×B×C as a positive integer.

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