GSO000 Problem 1

Since the object is pulled "slowly," its acceleration is zero and the forces on the object are always balanced.

Considering the force balance along the incline, the applied force $F$ equals the component of gravity along the incline $mg \sin\theta$ .

Therefore, the magnitude of the required force $F$ is:

F = mg \sin\theta

Using the definition of work $W = F \times d$ (force $\times$ distance), the positive work $W$ done by the force is:

W = F \times L = mgL \sin\theta

Substituting the given numerical values:

W = 5.0 \times 9.8 \times 10 \times \sin 30^\circ = 490 \times 0.5 = 245\text{ J}

Therefore, the answer is 245.

Answer: 245

Work and Energy on an Inclined Plane